Since Java 21, wrapper classes have played an increasingly sophisticated role in Java’s type system. Here’s everything you ...

The basic gist of it is that for this special 64-bit floating point value, the Java call Double.parseDouble ("2.2250738585072012e-308") will get stuck in an infinite loop.

Loss of Java double precision in math Binary numbers don’t always map cleanly to the base-10 number system. As a result, there can sometimes be a loss of precision in even the simplest of operation.